Open In App
Related Articles

GATE | GATE-CS-2015 (Set 3) | Question 56

Improve Article
Save Article
Like Article

Consider B+ tree in which the search key is 12 bytes long, block size is 1024 bytes, record pointer is 10 bytes long and block pointer is 8 bytes long. The maximum number of keys that can be accommodated in each non-leaf node of the tree is
(A) 49
(B) 50
(C) 51
(D) 52

Answer: (B)


Let m be the order of B+ tree

m(8)+(m-1)12 <= 1024  
[Note that record pointer is not needed in non-leaf nodes]

m <= 51

Since maximum order is 51, maximum number of keys is 50. 

Quiz of this Question

Level Up Your GATE Prep!
Embark on a transformative journey towards GATE success by choosing Data Science & AI as your second paper choice with our specialized course. If you find yourself lost in the vast landscape of the GATE syllabus, our program is the compass you need.

Last Updated : 28 Jun, 2021
Like Article
Save Article
Similar Reads