GATE | GATE-CS-2015 (Set 3) | Question 50
Let G be connected undirected graph of 100 vertices and 300 edges. The weight of a minimum spanning tree of G is 500. When the weight of each edge of G is increased by five, the weight of a minimum spanning tree becomes ________.
Explanation: Since there are 100 vertices, there must be 99 edges in Minimum Spanning Tree (MST).
When weight of every edge is increased by 5, the increment in weight of MST is = 99 * 5 = 495
Attention reader! Don’t stop learning now. Practice GATE exam well before the actual exam with the subject-wise and overall quizzes available in GATE Test Series Course.
Learn all GATE CS concepts with Free Live Classes on our youtube channel.
So new weight of MST is 500 + 495 which is 995
Quiz of this Question