Consider a 3 game tournament between two teams. Assume that every game results in either a win or loss. The team that wins two or more games wins the series. The probability for wining the first game for both teams is 1/2. The probability for a team to win a game after a win is 2/3. The probability of wining a game after a loss is 1/3. Note that the effect of only previous game is considered. What is the probability for a team to win the series after loosing first game.

**(A)** 1/9

**(B)** 1/6

**(C)** 2/9

**(D)** 1/3

**Answer:** **(C)** **Explanation:**

A team has 3 chances(games) to win tournament.

To win the tournament, a team must win atleast 2 games. Acc to question,

Team looses first chances. Now, to win, it is must to win left 2 games.

Probability to win the 2nd game : 1/3 (as previous game was a loss)

Probability to win the 3rd game : 2/3 (as previous game was a win)

So, Probability to win the tournament = 1/3 * 2/3

= 2/9

This solution is contributed by **Mohit Gupta.**

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