GATE | GATE-CS-2014-(Set-3) | Question 65

A system contains three programs and each requires three tape units for its operation. The minimum number of tape units which the system must have such that deadlocks never arise is _________.
(A) 6
(B) 7
(C) 8
(D) 9


Answer: (B)

Explanation: If 6 resources are there then it may be possible that all three process have 2 resources and waiting for 1 more resource. Therefore, all of them will have to wait indefinitely. If 7 resources are there, then atleast one must have 3 resources so deadlock can never occur.

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