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GATE | GATE-CS-2014-(Set-3) | Question 20
  • Difficulty Level : Medium
  • Last Updated : 18 Apr, 2014

Let A be a square matrix of size n x n. Consider the following program. What is the expected output?




C = 100
for i = 1 to n do
    for j = 1 to n do
    {
        Temp = A[i][j] + C
        A[i][j] = A[j][i]
        A[j][i] = Temp - C
    
for i = 1 to n do
    for j = 1 to n do
        Output(A[i][j]);

(A) The matrix A itself
(B) Transpose of matrix A
(C) Adding 100 to the upper diagonal elements and subtracting 100 from diagonal elements of A
(D) None of the above


Answer: (A)

Explanation: If we take look at the inner statements of first loops, we can notice that the statements swap A[i][j] and A[j][i] for all i and j. Since the loop runs for all elements, every element A[l][m] would be swapped twice, once for i = l and j = m and then for i = m and j = l. Swapping twice means the matrix doesn’t change.

Source: https://www.geeksforgeeks.org/data-structures-algorithms-set-34/

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