Let A be a square matrix of size n x n. Consider the following program. What is the expected output?
C = 100
for i = 1 to n do
for j = 1 to n do
{
Temp = A[i][j] + C
A[i][j] = A[j][i]
A[j][i] = Temp - C
}
for i = 1 to n do
for j = 1 to n do
Output(A[i][j]);
(A)
The matrix A itself
(B)
Transpose of matrix A
(C)
Adding 100 to the upper diagonal elements and subtracting 100 from diagonal elements of A
(D)
None of the above
Answer: (A)
Explanation:
If we take look at the inner statements of first loops, we can notice that the statements swap A[i][j] and A[j][i] for all i and j. Since the loop runs for all elements, every element A[l][m] would be swapped twice, once for i = l and j = m and then for i = m and j = l. Swapping twice means the matrix doesn’t change.
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Last Updated :
28 Jun, 2021
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