GATE | GATE-CS-2014-(Set-3) | Question 20
Let A be a square matrix of size n x n. Consider the following program. What is the expected output?
C = 100 for i = 1 to n do for j = 1 to n do { Temp = A[i][j] + C A[i][j] = A[j][i] A[j][i] = Temp - C } for i = 1 to n do for j = 1 to n do Output(A[i][j]); |
(A) The matrix A itself
(B) Transpose of matrix A
(C) Adding 100 to the upper diagonal elements and subtracting 100 from diagonal elements of A
(D) None of the above
Answer: (A)
Explanation: If we take look at the inner statements of first loops, we can notice that the statements swap A[i][j] and A[j][i] for all i and j. Since the loop runs for all elements, every element A[l][m] would be swapped twice, once for i = l and j = m and then for i = m and j = l. Swapping twice means the matrix doesn’t change.
Source: https://www.geeksforgeeks.org/data-structures-algorithms-set-34/
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