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GATE | GATE CS 2013 | Question 6

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Which one of the following is the tightest upper bound that represents the number of swaps required to sort n numbers using selection sort?
(A) O(log n)
(B) O(n)
(C) O(nLogn)
(D) O(n^2)


Answer: (B)

Explanation: To sort elements in increasing order, selection sort always picks the maximum element from remaining unsorted array and swaps it with the last element in the remaining array. So the number of swaps, it makes in n-1 which is O(n)

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Last Updated : 28 Jun, 2021
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