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GATE | GATE CS 2013 | Question 55

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  • Difficulty Level : Easy
  • Last Updated : 28 Jun, 2021
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Consider the FDs given in above question. The relation R is
(A) in 1NF, but not in 2NF.
(B) in 2NF, but not in 3NF.
(C) in 3NF, but not in BCNF.
(D) in BCNF

Answer: (A)

Explanation: The table is not in 2nd Normal Form as the non-prime attributes are dependent on subsets of candidate keys.

The candidate keys are AD, BD, ED and FD. In all of the following FDs, the non-prime attributes are dependent on a partial candidate key.

A -> BC
B -> CFH
F -> EG

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