GATE | GATE CS 2012 | Question 62
A political party orders an arch for the entrance to the ground in which the annual convention is being held. The profile of the arch follows the equation y = 2x – 0.1x2 where y is the height of the arch in meters. The maximum possible height of the arch is
(A) 8 meters
(B) 10 meters
(C) 12 meters
(D) 14 meters
Explanation: y = 2x – 0.1x2
dy/dx = 2 – 0.2x
So the value maximizes at 2 – 0.2x = 0
=> x = 10
=> y = 20 – 10 = 10 meters
Quiz of this Question
Attention reader! Don’t stop learning now. Practice GATE exam well before the actual exam with the subject-wise and overall quizzes available in GATE Test Series Course.
Learn all GATE CS concepts with Free Live Classes on our youtube channel.