Which of the given options provides the increasing order of asymptotic complexity of functions f1, f2, f3 and f4?
f1(n) = 2^n
f2(n) = n^(3/2)
f3(n) = nLogn
f4(n) = n^(Logn)
(A) f3, f2, f4, f1
(B) f3, f2, f1, f4
(C) f2, f3, f1, f4
(D) f2, f3, f4, f1
Answer: (A)
Explanation: nLogn is the slowest growing function, then comes n^(3/2), then n^(Logn).  Finally, 2^n is the fastest growing function.
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