GATE | GATE CS 2010 | Question 65
The Boolean expression for the output ‘f’ of the multiplexer shown below is
(A) (P(XOR)Q(XOR)R)’
(B) P(XOR)Q(XOR)R
(C) (P+Q+R)’
(D) P+Q+R
Answer: (B)
Explanation: For 4 to 1 mux truth table
SEL INPUT O/P
Q | P | R | R’ | R’ | R | F |
0 | 0 | X | X | X | 1 | 1 |
0 | 1 | X | X | 1 | X | 1 |
1 | 0 | X | 1 | X | X | 1 |
1 | 1 | 1 | X | X | X | 1 |
p’q’r+p’qr’+pq’r’+pqr
pXORqXORr
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