Consider the data given in above question. Assume that the memory is word addressable. After the execution of this program, the content of memory location 2010 is:
(A) 100
(B) 101
(C) 102
(D) 110
Answer: (A)
Explanation: Explanation:
Program stores results from 2000 to 2010.
It stores 110,109,108…..100 at 2010 location.
So at 2010 it stores 100
Because DEC R1 is instruction which decrements register value by 1.
So (A) is correct option.
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Last Updated :
19 Nov, 2018
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