The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocolis used, is:
(A) A
(B) B
(C) C
(D) D
Answer: (C)
Explanation: See Question 3 of https://www.geeksforgeeks.org/computer-networks-set-10/
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Last Updated :
28 Jun, 2021
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