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GATE | GATE-CS-2007 | Question 69
The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocolis used, is:
![GATECS200770]("http://www.geeksforgeeks.org/wp-content/uploads/gq/2014/02/GATECS200770.png")
(A)
A
(B)
B
(C)
C
(D)
D
Answer
Please comment below if you find anything wrong in the above post
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