GATE | GATE-CS-2007 | Question 24
Suppose we uniformly and randomly select a permutation from the 20! Permutations of 1, 2, 3 ,…..,20. What is the probability that 2 appears at an earlier position than any other even number in the selected permutation?
(A) 1/2
(B) 1/10
(C) 9!/20!
(D) Node of the above
Answer: (B)
Explanation: All even numbers have the same probability of being first (The odd numbers do not matter here). And there are 10 of them. The probability 2 comes before the other 9 evens is = 1/10.
So, option (B) is correct.
Quiz of this Question
Recommended Posts:
- GATE | GATE-CS-2015 (Mock Test) | Question 10
- GATE | GATE-CS-2015 (Mock Test) | Question 11
- GATE | GATE-CS-2015 (Mock Test) | Question 17
- GATE | GATE-CS-2015 (Mock Test) | Question 13
- GATE | GATE-CS-2015 (Mock Test) | Question 14
- GATE | GATE-CS-2015 (Mock Test) | Question 17
- GATE | GATE-CS-2015 (Mock Test) | Question 16
- GATE | GATE-CS-2015 (Mock Test) | Question 17
- GATE | GATE-CS-2015 (Mock Test) | Question 9
- GATE | GATE-CS-2015 (Mock Test) | Question 8
- GATE | GATE-CS-2015 (Mock Test) | Question 10
- GATE | GATE-CS-2015 (Mock Test) | Question 2
- GATE | GATE-CS-2015 (Mock Test) | Question 17
- GATE | GATE-CS-2015 (Mock Test) | Question 4
- GATE | GATE-CS-2015 (Mock Test) | Question 5