GATE | GATE-CS-2005 | Question 64
Consider the following circuit.
The flip-flops are positive edge triggered D FFs. Each state is designated as a two bit string Q0Q1. Let the initial state be 00. The state transition sequence is:
A)
B)
C)
D)
(A)
A
(B)
B
(C)
C
(D)
D
Answer: (D)
Explanation:
Q0 will toggle in every cycle because Q0\’ (Q0 complement) is fed as input to the D0 flip flop. For the D1 flip flop, D1 = Q0 ⊕ Q1\’ , i.e., Q0 XOR Q1\’. So, the bit pattern Q0 Q1 will be :
Q0 Q1
0 0
1 1
0 1
1 0
0 0
. .
. .
. .
Thus, the transition sequence will be So, D would be the correct choice. Please comment below if you find anything wrong in the above post.
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Last Updated :
29 Sep, 2021
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