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GATE | GATE-CS-2005 | Question 64

Last Updated : 29 Sep, 2021
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Consider the following circuit.  

The flip-flops are positive edge triggered D FFs. Each state is designated as a two bit string Q0Q1. Let the initial state be 00. The state transition sequence is:

 A)  
B) 
C)
D)

(A)

A

(B)

B

(C)

C

(D)

D



Answer: (D)

Explanation:

Q0 will toggle in every cycle because Q0\’ (Q0 complement) is fed as input to the D0 flip flop. For the D1 flip flop, D1 = Q0 ⊕ Q1\’ , i.e., Q0 XOR Q1\’. So, the bit pattern Q0 Q1 will be :

Q0     Q1

0      0

1      1

0      1

1      0

0      0

.      .

.      .

.      .

Thus, the transition sequence will be So, D would be the correct choice.    Please comment below if you find anything wrong in the above post.


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Please comment below if you find anything wrong in the above post


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