GATE | GATE-CS-2005 | Question 64
Consider the following circuit.
The flip-flops are positive edge triggered D FFs. Each state is designated as a two bit string Q0Q1. Let the initial state be 00. The state transition sequence is:
Explanation: Q0 will toggle in every cycle because Q0‘ (Q0 complement) is fed as input to the D0 flip flop.
For the D1 flip flop, D1 = Q0 ⊕ Q1‘ , i.e., Q0 XOR Q1‘.
So, the bit pattern Q0 Q1 will be :
Q0 Q1 0 0 1 1 0 1 1 0 0 0 . . . . . .
So, D would be the correct choice.
Please comment below if you find anything wrong in the above post.
Quiz of this Question
Attention reader! Don’t stop learning now. Practice GATE exam well before the actual exam with the subject-wise and overall quizzes available in GATE Test Series Course.
Learn all GATE CS concepts with Free Live Classes on our youtube channel.