• Courses
  • Tutorials
  • Jobs
  • Practice
  • Contests

GATE | GATE-CS-2003 | Question 54

Define languages L0 and L1 as follows :
L0 = {< M, w, 0 > | M halts on w}
L1 = {< M, w, 1 > | M does not halts on w} 
Here < M, w, i > is a triplet, whose first component. M is an encoding of a Turing Machine, second component, w, is a string, and third component, i, is a bit. Let L = L0 ∪ L1. Which of the following is true ?

(A)

L is recursively enumerable, but L\' is not

(B)

L\' is recursively enumerable, but L is not

(C)

Both L and L\' are recursive

(D)

Neither L nor L\' is recursively enumerable

Answer

Please comment below if you find anything wrong in the above post
Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Last Updated :
Share your thoughts in the comments