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GATE | GATE-CS-2003 | Question 48
Consider the following assembly language program for a hypothetical processor. A, B, and C are 8 bit registers. The meanings of various instructions are shown as comments.
| MOV B, # 0 | ; | B ← 0 | |
| MOV C, # 8 | ; | C ← 8 | |
| Z : | CMP C, # 0 | ; | compare C with 0 |
| JZX | ; | jump to X if zero flag is set | |
| SUB C, # 1 | ; | C ← C - 1 | |
| RRC A, # 1 | ; | right rotate A through carry by one bit. Thus: | |
| ; | if the initial values of A and the carry flag are a7...a0 and | ||
| ; | c0 respectively, their values after the execution of this | ||
| ; | instruction will be c0a7...a1 and a0 respectively. | ||
| JC Y | ; | jump to Y if carry flag is set | |
| JMP Z | ; | jump to Z | |
| Y : | ADD B, # 1 | ; | B ← B + 1 |
| JMP Z | ; | jump to Z | |
| X : |
(A)
the number of 0 bits in A0
(B)
the number of 1 bits in A0
(C)
A0
(D)
8
Answer
Please comment below if you find anything wrong in the above post
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