GATE | GATE-CS-2002 | Question 41

Four fair coins are tossed simultaneously. The probability that at least one head and one tail turn up is :
(A) 1/16
(B) 1/8
(C) 7/8
(D) 15/16

Answer: (C)

Explanation: There are only two cases (when all head or all tail) against the given output. So the required probability is (16-2)/16 = 7/8.

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