GATE | GATE-CS-2002 | Question 40
The Newton-Raphson iteration Xn + 1 = (Xn/2) + 3/(2Xn) can be used to solve the equation
(A) X2 = 3
(B) X3 = 3
(C) X2 = 2
(D) X3 = 2
Explanation: In Newton-Raphson’s method, We use the following formula to get the next value of f(x). f'(x) is derivative of f(x).
X2 = 3 f(x) = X2 - 3 Xn + 1 = Xn - (Xn2 - 3) / (2*Xn) = (Xn/2) + 3/(2xn)
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