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GATE | GATE-CS-2000 | Question 35

  • Last Updated : 19 Nov, 2018
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The following arrangement of master-slave flip flops has the initial state of P, Q as 0, 1 (respectively). After three clock cycles the output state P, Q is (re­spectively),

gatecs2000Q35

(A) 1, 0
(B) 1, 1
(C) 0, 0
(D) 0,1


Answer: (A)

Explanation: Given P = 0 ,  J = 1 and k = 1

  • JK flipflop toggles the input in ‘11’ state. Therefore, output of first flipflop at P is ‘1’.
  • Initial value of P is input for D flipflop. So, D = 0 .Therefore, output of second flipflop at Q is ‘0’.

    Thus, option (A) is the answer.

    Please comment below if you find anything wrong in the above post.


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