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GATE | GATE CS 1999 | Question 13

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Suppose we want to arrange the ii numbers stored in an array such that all negative values occur before all positive ones. Minimum number of exchanges required in the worst case is:
(A) n-1
(B) n
(C) n+1
(D) None of the above


Answer: (D)

Explanation: When we have ‘i’ numbers stored in an array, we have to swap all positive numbers with negative and in worst case positive numbers will be i/2.

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Last Updated : 12 Sep, 2018
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