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GATE | GATE CS 1997 | Question 38

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A micro instruction into be designed to specify a.  none or one of the three micro operations of one kind and b.  none or upto six micro operations of another kind The minimum number of bits in the micro-instruction is

(A)

9

(B)

5

(C)

8

(D)

None of the above


Answer: (C)

Explanation:

A) none or one of the three : vertical micro programming = log (n+1)= log (3+1) =2 bits

B) none or upto 6: horizontal micro programming = n bits = 6 bits

minimum no. of bits 6+2= 8 bits


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Last Updated : 19 Nov, 2018
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