Two dice are thrown simultaneously. The probability that at least one of them will have 6 facing up is
Explanation: There can be two cases:
- Case 1: Exactly one dice has 6 facing up and other dice can have any number from 1,2,3,4,5 facing up. There will be 5*2=10 such occurrences.
- Case 2: Both of the dices having 6 coming up. Only one possible case exists for the same.
Thus total favorable cases = 10+1 = 11
While total cases = 6*6=36
Which gives the desired probability as: 11/36.
This explanation is contributed by Pradeep Pandey.
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