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GATE | GATE CS 1996 | Question 47

  • Last Updated : 21 May, 2020

Consider the circuit in below figure. f implements

(A) (ABC)’ + A’BC’ + ABC
(B) A + B + C
(C) A ⊕ B ⊕ C
(D) AB + BC + CA

Answer: (C)

Explanation: A’B’C+A’BC’+AB’C’+ABC = A (EXOR) B (EXOR) C

So, option (C) is correct.

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