The average number of key comparisons done in a successful sequential search in a list of length it is
(A) log n
Explanation: If element is at 1 position then it requires 1 comparison.
If element is at 2 position then it requires 2 comparison.
If element is at 3 position then it requires 3 comparison.
Similarly , If element is at n position then it requires n comparison.
Total comparison = n(n+1)/2 For average comparison = (n(n+1)/2) / n = (n+1)/2
Option (D) is correct.
Quiz of this Question