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GATE | GATE 2017 MOCK II | Question 52

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A counting semaphore was initialized to 0, then 20 V operations were successfully completed on this semaphore, followed with 18 P operations, the resulting value of the semaphore is:

(A) 18
(B) 20
(C) 0
(D) 2


Answer: (D)

Explanation: 20V => increments the semaphore 20 times. Hence , the value becomes 20.
18P => decrements the semaphore 18 times. Hence , the value becomes 2.


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Last Updated : 28 Jun, 2021
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