GATE | GATE 2017 MOCK II | Question 52
A counting semaphore was initialized to 0, then 20 V operations were successfully completed on this semaphore, followed with 18 P operations, the resulting value of the semaphore is:
(A) 18
(B) 20
(C) 0
(D) 2
Answer: (D)
Explanation: 20V => increments the semaphore 20 times. Hence , the value becomes 20.
18P => decrements the semaphore 18 times. Hence , the value becomes 2.
Quiz of this Question
Last Updated :
28 Jun, 2021
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...