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Game of Nim with removal of one stone allowed
  • Difficulty Level : Basic
  • Last Updated : 14 Apr, 2021
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In Game of Nim, two players take turns removing objects from heaps or the pile of stones. 
Suppose two players A and B are playing the game. Each is allowed to take only one stone from the pile. The player who picks the last stone of the pile will win the game. Given N the number of stones in the pile, the task is to find the winner, if player A starts the game.
Examples : 
 

Input : N = 3.
Output : Player A

Player A remove stone 1 which is at the top, then Player B remove stone 2 
and finally player A removes the last stone.

Input : N = 15.
Output : Player A

For N = 1, player A will remove the only stone from the pile and wins the game. 
For N = 2, player A will remove the first stone and then player B remove the second or the last stone. So player B will win the game.
So, we can observe player A wins when N is odd and player B wins when N is even.
Below is the implementation of this approach: 
 

C++




// C++ program for Game of Nim with removal
// of one stone allowed.
#include<bits/stdc++.h>
using namespace std;
 
// Return true if player A wins,
// return false if player B wins.
bool findWinner(int N)
{
  // Checking the last bit of N.
  return N&1;
}
 
// Driven Program
int main()
{
  int N = 15;
  findWinner(N)? (cout << "Player A";):
                 (cout << "Player B";);
  return 0;
}

Java




// JAVA Code For Game of Nim with
// removal of one stone allowed
import java.util.*;
 
class GFG {
     
    // Return true if player A wins,
    // return false if player B wins.
    static int findWinner(int N)
    {
      // Checking the last bit of N.
      return N & 1;
    }
     
    /* Driver program to test above function */
    public static void main(String[] args)
    {
        int N = 15;
        if(findWinner(N)==1)
            System.out.println("Player A");
        else
             System.out.println("Player B");
           
    }
}
 
// This code is contributed by Arnav Kr. Mandal.

Python3




# Python3 code for Game of Nim with
# removal of one stone allowed.
 
# Return true if player A wins,
# return false if player B wins.
def findWinner( N ):
     
    # Checking the last bit of N.
    return N & 1
     
# Driven Program
N = 15
print("Player A" if findWinner(N) else "Player B")
 
# This code is contributed by "Sharad_Bhardwaj".

C#




// C# Code For Game of Nim with
// removal of one stone allowed
using System;
 
class GFG {
     
    // Return true if player A wins,
    // return false if player B wins.
    static int findWinner(int N)
    {
        // Checking the last bit of N.
        return N & 1;
    }
     
    /* Driver program to test above function */
    public static void Main()
    {
        int N = 15;
         
        if(findWinner(N) == 1)
            Console.Write("Player A");
        else
            Console.Write("Player B");
         
    }
}
 
// This code is contributed by vt_m.

PHP




<?php
// PHP program for Game of
// Nim with removal of one
// stone allowed.
 
// Return true if player A wins,
// return false if player B wins.
function findWinner($N)
{
     
// Checking the last bit of N.
return $N&1;
}
 
// Driver Code
$N = 15;
 
if(findWinner($N))
echo "Player A";
else
echo "Player B";
 
// This code is contributed by vt_m.
?>

Javascript




<script>
 
// JavaScript program For Game of Nim with
// removal of one stone allowed
 
   // Return true if player A wins,
    // return false if player B wins.
    function findWinner(N)
    {
     
      // Checking the last bit of N.
      return N & 1;
    }
 
// Driver code
        let N = 15;
        if(findWinner(N)==1)
            document.write("Player A");
        else
             document.write("Player B");
          
         // This code is contributed by sanjoy_2.
</script>

Output : 
 

Player A

Time Complexity: O(1).
This article is contributed by Anuj Chauhan. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 

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