Shadowing of static functions in Java

In Java, if the name of a derived class static function is the same as a base class static function then the base class static function shadows (or conceals) the derived class static function. For example, the following Java code prints “A.fun()”
Note: Static method is a class property, so if a static method is called from a class name or object having a class container then the method of that class is called not the object’s method.

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// file name: Main.java
  
// Parent class
class A {
    static void fun()
    {
        System.out.println("A.fun()");
    }
}
  
// B is inheriting A
// Base class
class B extends A {
    static void fun()
    {
        System.out.println("B.fun()");
    }
}
  
// Driver Method
public class Main {
    public static void main(String args[])
    {
        A a = new B();
        a.fun(); // prints A.fun();
  
        // B a = new B();
        // a.fun(); // prints B.fun()
  
        // the variable type decides the method
        // being invoked, not the assigned object type
    }
}

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Output:

A.fun()

Note: If we make both A.fun() and B.fun() as non-static then the above program would print “B.fun()”. While both methods are static types, the variable type decides the method being invoked, not the assigned object type

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