What is use of %n in printf() ?
In C printf(), %n is a special format specifier which instead of printing something causes printf() to load the variable pointed by the corresponding argument with a value equal to the number of characters that have been printed by printf() before the occurrence of %n.
#include<stdio.h> int main() { int c; printf("geeks for %ngeeks ", &c); printf("%d", c); getchar(); return 0; } |
chevron_right
filter_none
The above program prints “geeks for geeks 10”. The first printf() prints “geeks for geeks”. The second printf() prints 10 as there are 10 characters printed (the 10 characters are “geeks for “) before %n in first printf() and c is set to 10 by first printf().
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Recommended Posts:
- Nested printf (printf inside printf) in C
- Use of & in scanf() but not in printf()
- How to print % using printf()?
- Execution of printf with ++ operators
- Cin-Cout vs Scanf-Printf
- Passing NULL to printf in C
- How to change the output of printf() in main() ?
- puts() vs printf() for printing a string
- Return values of printf() and scanf() in C/C++
- What is the difference between printf, sprintf and fprintf?
- Slack Bytes in Structures : Explained with Example
- Difference between Iterators and Pointers in C/C++ with Examples
- C program to count number of vowels and consonants in a String
- Nested Loops in C with Examples
- Must Do Coding Questions for Companies like Amazon, Microsoft, Adobe, ...
- How to find the parent class name with known class in jQuery ?
- D3.js | d3.entries() Function
- Find the winner of the Game to Win by erasing any two consecutive similar alphabets
- Find the integers that doesnot ends with T1 or T2 when squared and added X
