How does “void *” differ in C and C++?

C allows a void* pointer to be assigned to any pointer type without a cast, whereas C++ does not; this idiom appears often in C code using malloc memory allocation. For example, the following is valid in C but not C++:

  void* ptr;
  int *i = ptr; /* Implicit conversion from void* to int* */

or similarly:

  int *j = malloc(sizeof(int) * 5); /* Implicit conversion from void* to int* */

In order to make the code compile in both C and C++, one must use an explicit cast:

  void* ptr;
  int *i = (int *) ptr;
  int *j = (int *) malloc(sizeof(int) * 5);


Please write to us at to report any issue with the above content.

Recommended Posts:

2.1 Average Difficulty : 2.1/5.0
Based on 59 vote(s)