fmt.Scanln() Function in Golang With Examples
Last Updated :
05 Dec, 2022
In Go language, fmt package implements formatted I/O with functions analogous to C’s printf() and scanf() function. The fmt.Scanln() function in Go language scans the input texts which is given in the standard input, reads from there and stores the successive space-separated values into successive arguments. This function stops scanning at a newline and after the final item, there must be a newline or EOF. Moreover, this function is defined under the fmt package. Here, you need to import the “fmt” package in order to use these functions.
Syntax:
func Scanln(a ...interface{}) (n int, err error)
Here, “a …interface{}” receives each given texts. Returns: It returns the number of items successfully scanned.
Example 1:
C
package main
import (
"fmt"
)
func main() {
var name string
var alphabet_count int
fmt.Scanln(&name)
fmt.Scanln(&alphabet_count)
fmt.Printf("%s %d",
name, alphabet_count)
}
|
Input:
GFG 3
Output:
GFG 0
Example 2:
C
package main
import (
"fmt"
)
func main() {
var name string
var alphabet_count int
fmt.Scanln(&name)
fmt.Scanln(&alphabet_count)
fmt.Printf("%s %d",
name, alphabet_count)
}
|
Input:
GeeksforGeeks \n 13
Output:
GeeksforGeeks 0
In the above example, it can be seen that standard input takes the value of “GeeksforGeeks \n 13” but it returns output as “GeeksforGeeks 0” this is because of this function stop scanning at new line (\n).
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