Open In App

fmt.Scanln() Function in Golang With Examples

Last Updated : 05 Dec, 2022
Improve
Improve
Like Article
Like
Save
Share
Report

In Go language, fmt package implements formatted I/O with functions analogous to C’s printf() and scanf() function. The fmt.Scanln() function in Go language scans the input texts which is given in the standard input, reads from there and stores the successive space-separated values into successive arguments. This function stops scanning at a newline and after the final item, there must be a newline or EOF. Moreover, this function is defined under the fmt package. Here, you need to import the “fmt” package in order to use these functions. 

Syntax:

func Scanln(a ...interface{}) (n int, err error)

Here, “a …interface{}” receives each given texts. Returns: It returns the number of items successfully scanned.

 Example 1: 

C




// Golang program to illustrate the usage of
// fmt.Scanln() function
 
// Including the main package
package main
 
// Importing fmt
import (
    "fmt"
)
 
// Calling main
func main() {
 
    // Declaring some variables
    var name string
    var alphabet_count int
 
    // Calling Scanln() function for
    // scanning and reading the input
    // texts given in standard input
    fmt.Scanln(&name)
    fmt.Scanln(&alphabet_count)
 
    // Printing the given texts
    fmt.Printf("%s %d",
               name, alphabet_count)
 
}


Input:

GFG 3

Output:

GFG 0

Example 2: 

C




// Golang program to illustrate the usage of
// fmt.Scanln() function
 
// Including the main package
package main
 
// Importing fmt
import (
    "fmt"
)
 
// Calling main
func main() {
 
    // Declaring some variables
    var name string
    var alphabet_count int
 
    // Calling Scanln() function for
    // scanning and reading the input
    // texts given in standard input
    fmt.Scanln(&name)
    fmt.Scanln(&alphabet_count)
 
    // Printing the given texts
    fmt.Printf("%s %d",
               name, alphabet_count)
 
}


Input:

GeeksforGeeks \n 13

Output:

GeeksforGeeks 0

In the above example, it can be seen that standard input takes the value of “GeeksforGeeks \n 13” but it returns output as “GeeksforGeeks 0” this is because of this function stop scanning at new line (\n).



Like Article
Suggest improvement
Previous
Next
Share your thoughts in the comments

Similar Reads