fmt.Println() Function in Golang With Examples

In Go language, fmt package implements formatted I/O with functions analogous to C’s printf() and scanf() function. The fmt.Println() function in Go language formats using the default formats for its operands and writes to standard output. Here spaces are always added between operands and a newline is appended at the end. Moreover, this function is defined under the fmt package. Here, you need to import the “fmt” package in order to use these functions.

Syntax:

func Println(a ...interface{}) (n int, err error)

Here, “a …interface{}” contains some strings including specified constant variables.

Return Value: It returns the number of bytes written and any write error encountered.

Example 1:



filter_none

edit
close

play_arrow

link
brightness_4
code

// Golang program to illustrate the usage of
// fmt.Println() function
  
// Including the main package
package main
  
// Importing fmt
import (
    "fmt"
)
  
// Calling main
func main() {
  
    // Declaring some const variables
    const name, dept = "GeeksforGeeks", "CS"
  
    // Calling Println() function
    fmt.Println(name, "is", "a", dept, "Portal.")
  
    // It is conventional not to worry about any
    // error returned by Println.
  
}

chevron_right


Output:

GeeksforGeeks is a CS Portal.

In the above code, it can be seen that the function Println() is not containing any space within the specified strings still in output is print space that can be seen from the above output.

Example 2:

filter_none

edit
close

play_arrow

link
brightness_4
code

// Golang program to illustrate the usage of
// fmt.Println() function
  
// Including the main package
package main
  
// Importing fmt
import (
    "fmt"
)
  
// Calling main
func main() {
  
    // Declaring some const variables
    const num1, num2, num3, num4 = 5, 10, 15, 50
  
    // Calling Println() function
    fmt.Println(num1, "+", num2, "=", num3)
    fmt.Println(num1, "*", num2, "=", num4)
  
    // It is conventional not to worry about any
    // error returned by Println.
  
}

chevron_right


Output:

5 + 10 = 15
5 * 10 = 50

In the above code, it can be seen that the function Println() is not using any newline (\n) still in the output it prints new line that can be seen from above shown output.




My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.


Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.