Floor and Ceil from a BST

There are numerous applications we need to find floor (ceil) value of a key in a binary search tree or sorted array. For example, consider designing memory management system in which free nodes are arranged in BST. Find best fit for the input request.

Ceil Value Node: Node with smallest data larger than or equal to key value.

Imagine we are moving down the tree, and assume we are root node. The comparison yields three possibilities,



A) Root data is equal to key. We are done, root data is ceil value.

B) Root data < key value, certainly the ceil value can’t be in left subtree. Proceed to search on right subtree as reduced problem instance.

C) Root data > key value, the ceil value may be in left subtree. We may find a node with is larger data than key value in left subtree, if not the root itself will be ceil node.

Here is the code for ceil value.

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// Program to find ceil of a given value in BST
#include <bits/stdc++.h>
using namespace std;
  
/* A binary tree node has key, left child and right child */
class node {
public:
    int key;
    node* left;
    node* right;
};
  
/* Helper function that allocates a new node with the given key and 
NULL left and right pointers.*/
node* newNode(int key)
{
    node* Node = new node();
    Node->key = key;
    Node->left = NULL;
    Node->right = NULL;
    return (Node);
}
  
// Function to find ceil of a given input in BST. If input is more
// than the max key in BST, return -1
int Ceil(node* root, int input)
{
    // Base case
    if (root == NULL)
        return -1;
  
    // We found equal key
    if (root->key == input)
        return root->key;
  
    // If root's key is smaller, ceil must be in right subtree
    if (root->key < input)
        return Ceil(root->right, input);
  
    // Else, either left subtree or root has the ceil value
    int ceil = Ceil(root->left, input);
    return (ceil >= input) ? ceil : root->key;
}
  
// Driver program to test above function
int main()
{
    node* root = newNode(8);
  
    root->left = newNode(4);
    root->right = newNode(12);
  
    root->left->left = newNode(2);
    root->left->right = newNode(6);
  
    root->right->left = newNode(10);
    root->right->right = newNode(14);
  
    for (int i = 0; i < 16; i++)
        cout << i << " " << Ceil(root, i) << endl;
  
    return 0;
}
  
// This code is contributed by rathbhupendra

chevron_right


C

filter_none

edit
close

play_arrow

link
brightness_4
code

// Program to find ceil of a given value in BST
#include <stdio.h>
#include <stdlib.h>
  
/* A binary tree node has key, left child and right child */
struct node {
    int key;
    struct node* left;
    struct node* right;
};
  
/* Helper function that allocates a new node with the given key and
NULL left and right pointers.*/
struct node* newNode(int key)
{
    struct node* node = (struct node*)malloc(sizeof(struct node));
    node->key = key;
    node->left = NULL;
    node->right = NULL;
    return (node);
}
  
// Function to find ceil of a given input in BST. If input is more
// than the max key in BST, return -1
int Ceil(struct node* root, int input)
{
    // Base case
    if (root == NULL)
        return -1;
  
    // We found equal key
    if (root->key == input)
        return root->key;
  
    // If root's key is smaller, ceil must be in right subtree
    if (root->key < input)
        return Ceil(root->right, input);
  
    // Else, either left subtree or root has the ceil value
    int ceil = Ceil(root->left, input);
    return (ceil >= input) ? ceil : root->key;
}
  
// Driver program to test above function
int main()
{
    struct node* root = newNode(8);
  
    root->left = newNode(4);
    root->right = newNode(12);
  
    root->left->left = newNode(2);
    root->left->right = newNode(6);
  
    root->right->left = newNode(10);
    root->right->right = newNode(14);
  
    for (int i = 0; i < 16; i++)
        printf("%d %d\n", i, Ceil(root, i));
  
    return 0;
}

chevron_right


Java

filter_none

edit
close

play_arrow

link
brightness_4
code

// Java program to find ceil of a given value in BST 
  
class Node { 
  
    int data; 
    Node left, right; 
  
    Node(int d) 
    
        data = d; 
        left = right = null
    
  
class BinaryTree { 
  
    Node root; 
  
    // Function to find ceil of a given input in BST. 
    // If input is more than the max key in BST, 
    // return -1 
    int Ceil(Node node, int input) 
    
  
        // Base case 
        if (node == null) { 
            return -1
        
  
        // We found equal key 
        if (node.data == input) { 
            return node.data; 
        
  
        // If root's key is smaller, 
        // ceil must be in right subtree 
        if (node.data < input) { 
            return Ceil(node.right, input); 
        
  
        // Else, either left subtree or root
        // has the ceil value 
        int ceil = Ceil(node.left, input); 
          
        return (ceil >= input) ? ceil : node.data; 
    
  
    // Driver Code
    public static void main(String[] args) 
    
        BinaryTree tree = new BinaryTree(); 
        tree.root = new Node(8); 
        tree.root.left = new Node(4); 
        tree.root.right = new Node(12); 
        tree.root.left.left = new Node(2); 
        tree.root.left.right = new Node(6); 
        tree.root.right.left = new Node(10); 
        tree.root.right.right = new Node(14); 
        for (int i = 0; i < 16; i++) { 
              
            System.out.println(i + " "
                        tree.Ceil(tree.root, i)); 
        
    
  
// This code has been contributed by Mayank Jaiswal 

chevron_right


Python

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python program to find ceil of a given value in BST
  
# A Binary tree node
class Node:
      
    # Constructor to create a new node
    def __init__(self, data):
        self.key = data
        self.left = None
        self.right = None
  
# Function to find ceil of a given input in BST. If input
# is more than the max key in BST, return -1
def ceil(root, inp):
      
    # Base Case
    if root == None:
        return -1
      
    # We found equal key
    if root.key == inp :
        return root.key 
      
    # If root's key is smaller, ceil must be in right subtree
    if root.key < inp:
        return ceil(root.right, inp)
      
    # Else, either left subtre or root has the ceil value
    val = ceil(root.left, inp)
    return val if val >= inp else root.key 
  
# Driver program to test above function
root = Node(8)
  
root.left = Node(4)
root.right = Node(12)
  
root.left.left = Node(2)
root.left.right = Node(6)
  
root.right.left = Node(10)
root.right.right = Node(14)
  
for i in range(16):
    print "% d % d" %(i, ceil(root, i))
  
# This code is contributed by Nikhil Kumar Singh(nickzuck_007)

chevron_right


C#

filter_none

edit
close

play_arrow

link
brightness_4
code

using System;
  
// C# program to find ceil of a given value in BST
  
public class Node {
  
    public int data;
    public Node left, right;
  
    public Node(int d)
    {
        data = d;
        left = right = null;
    }
}
  
public class BinaryTree {
  
    public static Node root;
  
    // Function to find ceil of a given input in BST. If input is more
    // than the max key in BST, return -1
    public virtual int Ceil(Node node, int input)
    {
  
        // Base case
        if (node == null) {
            return -1;
        }
  
        // We found equal key
        if (node.data == input) {
            return node.data;
        }
  
        // If root's key is smaller, ceil must be in right subtree
        if (node.data < input) {
            return Ceil(node.right, input);
        }
  
        // Else, either left subtree or root has the ceil value
        int ceil = Ceil(node.left, input);
        return (ceil >= input) ? ceil : node.data;
    }
  
    // Driver program to test the above functions
    public static void Main(string[] args)
    {
        BinaryTree tree = new BinaryTree();
        BinaryTree.root = new Node(8);
        BinaryTree.root.left = new Node(4);
        BinaryTree.root.right = new Node(12);
        BinaryTree.root.left.left = new Node(2);
        BinaryTree.root.left.right = new Node(6);
        BinaryTree.root.right.left = new Node(10);
        BinaryTree.root.right.right = new Node(14);
        for (int i = 0; i < 16; i++) {
            Console.WriteLine(i + " " + tree.Ceil(root, i));
        }
    }
}
  
// This code is contributed by Shrikant13

chevron_right



Output:

0  2
1  2
2  2
3  4
4  4
5  6
6  6
7  8
8  8
9  10
10  10
11  12
12  12
13  14
14  14
15  -1

Exercise:

1. Modify above code to find floor value of input key in a binary search tree.

2. Write neat algorithm to find floor and ceil values in a sorted array. Ensure to handle all possible boundary conditions.

— Venki. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.



My Personal Notes arrow_drop_up

Improved By : shrikanth13, rathbhupendra



Article Tags :
Practice Tags :


4


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.