Given a linked list, find its first non-repeating integer element.
Input : 10->20->30->10->20->40->30->NULL Output :First Non-repeating element is 40. Input :1->1->2->2->3->4->3->4->5->NULL Output :First Non-repeating element is 5. Input :1->1->2->2->3->4->3->4->NULL Output :No NOn-repeating element is found.
1) Create a hash table and marked all element as zero.
2) Traverse the linked list and count the frequency of all the element in hashtable.
3) Traverse the linked list again and see the element who’s frequency is 1 in hashtable.
The above solution requires two traversals of linked list. In case we have many repeating elements, we can save one traversal by storing positions also in hash table. Please refer last method of Given a string, find its first non-repeating character for details.
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