Skip to content
Related Articles
Open in App
Not now

Related Articles

Finding the Square Root of Given Number in Golang

Improve Article
Save Article
Like Article
  • Last Updated : 01 Apr, 2020
Improve Article
Save Article
Like Article

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the square root of the specified number with the help of the Sqrt() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Sqrt() function.

Syntax:

func Sqrt(a float64) float64
  • If you pass +Inf in this function, then this function will return +Inf.
  • If you pass +0 or -0 in this function, then this function will return +0 or -0.
  • If the value of a < -1, then this function will return NaN.
  • If you pass NaN in this function, then this function will return NaN.

Example 1:




// Golang program to illustrate how to find
// the square root of the given number
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding square root 
    // of the given number
    // Using Sqrt() function
    res_1 := math.Sqrt(0)
    res_2 := math.Sqrt(-100)
    res_3 := math.Sqrt(math.Inf(1))
    res_4 := math.Sqrt(math.NaN())
    res_5 := math.Sqrt(36)
  
    // Displaying the result
    fmt.Printf("Result 1: %.1f", res_1)
    fmt.Printf("\nResult 2: %.1f", res_2)
    fmt.Printf("\nResult 3: %.1f", res_3)
    fmt.Printf("\nResult 4: %.1f", res_4)
    fmt.Printf("\nResult 5: %.1f", res_5)
  
}

Output:

Result 1: 0.0
Result 2: NaN
Result 3: +Inf
Result 4: NaN
Result 5: 6.0

Example 2:




// Golang program to illustrate how to find
// the square root of the given number
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding square root 
    // of the given number
    // Using Sqrt() function
    nvalue_1 := math.Sqrt(100)
    nvalue_2 := math.Sqrt(25)
    res := nvalue_1 + nvalue_2
    fmt.Printf("%.3f + %.3f = %.3f",
            nvalue_1, nvalue_2, res)
  
}

Output:

10.000 + 5.000 = 15.000

My Personal Notes arrow_drop_up
Like Article
Save Article
Related Articles

Start Your Coding Journey Now!