# Finding the Square Root of Given Number in Golang

• Last Updated : 01 Apr, 2020

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the square root of the specified number with the help of the Sqrt() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Sqrt() function.

Syntax:

`func Sqrt(a float64) float64`
• If you pass +Inf in this function, then this function will return +Inf.
• If you pass +0 or -0 in this function, then this function will return +0 or -0.
• If the value of a < -1, then this function will return NaN.
• If you pass NaN in this function, then this function will return NaN.

Example 1:

 `// Golang program to illustrate how to find``// the square root of the given number`` ` `package main`` ` `import (``    ``"fmt"``    ``"math"``)`` ` `// Main function``func main() {`` ` `    ``// Finding square root ``    ``// of the given number``    ``// Using Sqrt() function``    ``res_1 := math.Sqrt(0)``    ``res_2 := math.Sqrt(-100)``    ``res_3 := math.Sqrt(math.Inf(1))``    ``res_4 := math.Sqrt(math.NaN())``    ``res_5 := math.Sqrt(36)`` ` `    ``// Displaying the result``    ``fmt.Printf(``"Result 1: %.1f"``, res_1)``    ``fmt.Printf(``"\nResult 2: %.1f"``, res_2)``    ``fmt.Printf(``"\nResult 3: %.1f"``, res_3)``    ``fmt.Printf(``"\nResult 4: %.1f"``, res_4)``    ``fmt.Printf(``"\nResult 5: %.1f"``, res_5)`` ` `}`

Output:

```Result 1: 0.0
Result 2: NaN
Result 3: +Inf
Result 4: NaN
Result 5: 6.0
```

Example 2:

 `// Golang program to illustrate how to find``// the square root of the given number`` ` `package main`` ` `import (``    ``"fmt"``    ``"math"``)`` ` `// Main function``func main() {`` ` `    ``// Finding square root ``    ``// of the given number``    ``// Using Sqrt() function``    ``nvalue_1 := math.Sqrt(100)``    ``nvalue_2 := math.Sqrt(25)``    ``res := nvalue_1 + nvalue_2``    ``fmt.Printf(``"%.3f + %.3f = %.3f"``,``            ``nvalue_1, nvalue_2, res)`` ` `}`

Output:

`10.000 + 5.000 = 15.000`

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