Given an integer N. The task is to write a program to find the parity of the given number.
Note: Parity of a number is used to define if the total number of set-bits(1-bit in binary representation) in a number is even or odd. If the total number of set-bits in the binary representation of a number is even then the number is said to have even parity, otherwise, it will have odd parity.
Input : N = 13 Output : Odd Parity Binary representation of 13 is (1101) Input : N = 9 (1001) Output : Even Parity
The parity of a number represented by 32-bits can be efficiently calculated by performing the following operations.
Let the given number be x, then perform the below operations:
- y = x^(x>>1)
- y = y^(y>>2)
- y = y^(y>>4)
- y = y^(y>>8)
- y = y^(y>>16)
Now, the rightmost bit in y will represent the parity of x. If the rightmost bit is 1, then x will have odd parity and if it is 0 then x will have even parity.
So, in order to extract the last bit of y, perform bit-wise AND operation of y with 1.
if(y&1==1) odd Parity else even Parity
Below is the implementation of the above approach:
Even Parity Odd Parity
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