Finding the Ceiling Value of Specified Number in Golang
Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the least integer value greater than or equal to the specified number with the help of the Ceil() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Ceil() function.
Syntax:
func Ceil(y float64) float64
- If you pass +Inf or -Inf in this function, then this function will return +Inf or -Inf.
- If you pass -0 or +0 in this function, then this function will return -0 or +0.
- If you pass NaN in this function, then this function will return NaN.
Example 1:
package main
import (
"fmt"
"math"
)
func main() {
res_1 := math.Ceil(math.Pi / 2)
res_2 := math.Ceil(34.567)
res_3 := math.Ceil(-12.34)
fmt.Printf( "Result 1: %.1f" , res_1)
fmt.Printf( "\nResult 2: %.1f" , res_2)
fmt.Printf( "\nResult 3: %.1f" , res_3)
}
|
Output:
Result 1: 2.0
Result 2: 35.0
Result 3: -12.0
Example 2:
package main
import (
"fmt"
"math"
)
func main() {
nvalue_1 := math.Sin(math.Pi / 4)
nvalue_2 := math.Sin(math.Pi / 6)
res := nvalue_1 + nvalue_2
fmt.Printf( "%.1f + %.1f = %.1f" ,
nvalue_1, nvalue_2, res)
fmt.Println( "\nRound off the result: " ,
math.Ceil(res))
}
|
Output:
0.7 + 0.5 = 1.2
Round off result: 2
Last Updated :
01 Apr, 2020
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...