Given the radius and coordinates of the centre of a circle. Find the quadrant in which another given coordinate (X, Y) lies with respect to the centre of circle if the point lies inside the circle. Else print an error “Lies outside the circle”.
If the point lies at the centre of circle output 0 or if the point lies on any of the axes and inside the circle output the next quadrant in anti-clock direction.
Input : Centre = (0, 0), Radius = 10
(X, Y) = (10, 10)
Output : Lies Outside the Circle
Input : Centre = (0, 3), Radius = 2
(X, Y) = (1, 4)
Output : 1 (I quadrant)
Let center be (x’, y’)
Equation of circle is – (Eq. 1)
According to this equation,
If point (x, y) lies outside of circle
If point (x, y) lies on the circle
If point (x, y) lies inside of circle
To check position of point with respect to circle:-
1. Put given coordinates in equation 1. 2. If it is greater than 0 coordinate lies outside circle. 3. If point lies inside circle find the quadrant within the circle. Check the point with respect to centre of circle.
Below is the implementation of above idea :
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