Finding Minimum Element of Java ArrayList
For finding the minimum element in the ArrayList(This class is found in java.util package), complete traversal of the ArrayList is required. There is an inbuilt function in ArrayList class to find minimum element in the ArrayList, i.e. Time Complexity is O(N), where N is the size of ArrayList, Let’s discuss both the methods.
Example
Input : ArrayList = {2, 9, 1, 3, 4}
Output: Min = 1
Input : ArrayList = {6, 7, 2, 8}
Output: Min = 2
Approach 1:
- Create on variable and initialize it with the first element of ArrayList.
- Start traversing the ArrayList.
- If the current element is less than variable, then update the variable with the current element in ArrayList.
- In the end, print that variable.
Below is the implementation of the above approach:
Java
import java.util.ArrayList;
import java.util.Collections;
class MinElementInArrayList {
public static void main(String[] args)
{
ArrayList<Integer> myList
= new ArrayList<Integer>();
myList.add( 16 );
myList.add( 26 );
myList.add( 3 );
myList.add( 52 );
myList.add( 70 );
myList.add( 12 );
int minimum = myList.get( 0 );
for ( int i = 1 ; i < myList.size(); i++) {
if (minimum > myList.get(i))
minimum = myList.get(i);
}
System.out.println( "Minimum element in ArrayList = "
+ minimum);
}
}
|
Output
Minimum element in ArrayList = 3
Approach 2:
‘min’ method of java collection class can be used to find ArrayList. ‘min’ method returns the minimum element of the collection according to the natural ordering of the elements.
Java
import java.util.ArrayList;
import java.util.Collections;
class MinElementInArrayList {
public static void main(String[] args)
{
ArrayList<Integer> myList
= new ArrayList<Integer>();
myList.add( 16 );
myList.add( 26 );
myList.add( 3 );
myList.add( 52 );
myList.add( 70 );
myList.add( 12 );
System.out.println( "Minimum Element in ArrayList = "
+ Collections.min(myList));
}
}
|
Output
Minimum Element in ArrayList = 3
Last Updated :
04 Jan, 2021
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