# Finding Maximum Element of Java Vector

• Last Updated : 05 Jul, 2021

Vector implements a dynamic array that means it can grow or shrink as required. Like an array, it contains components that can be accessed using an integer index. We know two ways for declaring array i.e. either with a fixed size of array or size enter as per the demand of the user according to which array is allocated in memory.

int Array_name[Fixed_size] ;

int array_name[variable_size] ;

In both ways, we land up wasting memory so, in order to properly utilize memory optimization, Vectors were introduced. We have to find out the maximum element in the given Java vector.

Examples:

Input: [1,2,3,4,5]
Output: 5
Input: [88,23,76,90,56]
Output: 90

Approach 1: Using a Predefined Function

• To find the minimum element of a given vector we use the java.util.Collections.max() method.
• This directly finds the maximum value in the vector.

## Java

 // Java program to find// maximum element in java vector import java.io.*;import java.util.Collections;import java.util.Vector;public class GFG {     public static void main(String args[])         Vector vec = new Vector();         vec.add(1);        vec.add(2);        vec.add(3);        vec.add(4);        vec.add(5);         System.out.println("Vector elements: " + vec);           System.out.println("The maximum element of the Vector is: "         + Collections.max(vec));    } }
Output

Vector elements: [1, 2, 3, 4, 5]
The maximum element of the Vector is: 5

Worst Case Time Complexity: O(n) where n is the number of elements present in the vector.

Approach 2: Comparing each element present in Vector

• First, we will initialize a vector let’s say v, then we will store values in that vector.
• Next, we will take a variable, let us say maxNumber and assign the maximum value possible.
• Traverse till the end of vector and compare each element of a vector with maxNumber.
• If the element present in the vector is greater than maxNumber, then update maxNumber to that value.
• Print maxNumber.

## Java

 // Java program to find largest element// present in Vector via comparison   import java.io.*;   // Importing Vector Class import java.util.Vector;   // Importing Iterator Classimport java.util.Iterator;   class GFG {         // Main Method    public static void main(String[] args)    {        // initializing vector of Integer type        Vector v = new Vector();                 // Adding elements in vector        v.add(10);        v.add(20);        v.add(30);        v.add(40);        v.add(50);                 // Assigning min value possible        int maxValue = Integer.MIN_VALUE;                 // Creating an iterator to traverse through vector        // in the beginning itr will point to index just        // before first element        Iterator itr = v.iterator();                 // See if there is any next element        while (itr.hasNext())         {            // Moving iterator to next element            int element = (Integer)itr.next();               // Comparing if element is larger than maxValue            if (element > maxValue)             {                // Update maxValue                maxValue = element;            }        }                 // Print maxVaue        System.out.println( "The largest element present in Vector is : "            + maxValue);    }}
Output
The largest element present in Vector is : 50

Time Complexity: O(n) where n is the number of elements present in the vector.

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