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Finding Inverse Hyperbolic Cosine of Specified Number in Golang
  • Last Updated : 01 Apr, 2020

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the inverse hyperbolic cosine of the specified number with the help of Acosh() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Acosh() function.

Syntax:

func Acosh(y float64) float64
  • If you pass +Inf in this function, then this function will return +Inf.
  • If the value y < 1, then this function will return NaN.
  • If you pass NaN in this function, then this function will return NaN.

Example 1:




// Golang program to illustrate how to find
// inverse hyperbolic cosine of the given
// number
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding the inverse hyperbolic
    // cosine of the given value
    // Using Acosh() function
    res_1 := math.Acosh(math.Pi / 2)
    res_2 := math.Acosh(math.Inf(-3))
    res_3 := math.Acosh(0)
    res_4 := math.Acosh(math.NaN())
    res_5 := math.Acosh(1)
  
    // Displaying the result
    fmt.Printf("Result 1: %.1f", res_1)
    fmt.Printf("\nResult 2: %.1f", res_2)
    fmt.Printf("\nResult 3: %.1f", res_3)
    fmt.Printf("\nResult 4: %.1f", res_4)
    fmt.Printf("\nResult 5: %.1f", res_5)
}

Output:

Result 1: 1.0
Result 2: NaN
Result 3: NaN
Result 4: NaN
Result 5: 0.0

Example 2:




// Golang program to illustrate how to find
// inverse hyperbolic cosine of the given
// number
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding inverse hyperbolic
    // cosine of the given number
    nvalue_1 := math.Acosh(math.Pi / 3)
    nvalue_2 := math.Acosh(math.Pi / 6)
  
    // Sum of the given values
    res := nvalue_1 + nvalue_2
  
    // Displaying results
    fmt.Printf("%.1f + %.1f = %.1f",
           nvalue_1, nvalue_2, res)
  
}

Output:

0.3 + NaN = NaN



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