Given an integer *N*, the task is to find two numbers *a and b* such that *a * b = N* and *a + b = N*. Print “NO” if no such numbers are possible. **Examples:**

Input:N = 69Output:a = 67.9851

b = 1.01493Input:N = 1Output:NO

**Approach:** If observed carefully, we are given with sum and product of roots of a quadratic equation.

If *N ^{2} – 4*N < 0* then only imaginary roots are possible for the equation, hence “NO” will be the answer. Else

*a and b*will be:

a = ( N + sqrt(

N) ) / 2^{2}– 4*N

b = ( N – sqrt(N) ) / 2^{2}– 4*N

Below is the implementation of the above approach:

## C++

`// C++ program to find a and b` `// such that a*b=N and a+b=N` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to return the smallest string` `void` `findAandB(` `double` `N)` `{` ` ` `double` `val = N * N - 4.0 * N;` ` ` `// Not possible` ` ` `if` `(val < 0) {` ` ` `cout << ` `"NO"` `;` ` ` `return` `;` ` ` `}` ` ` `// find a and b` ` ` `double` `a = (N + ` `sqrt` `(val)) / 2.0;` ` ` `double` `b = (N - ` `sqrt` `(val)) / 2.0;` ` ` `cout << ` `"a = "` `<< a << endl;` ` ` `cout << ` `"b = "` `<< b << endl;` `}` `// Driver Code` `int` `main()` `{` ` ` `double` `N = 69.0;` ` ` `findAandB(N);` ` ` `return` `0;` `}` |

## Java

`// Java program to find a and b` `// such that a*b=N and a+b=N` `class` `GFG{` `// Function to return the smallest string` `static` `void` `findAandB(` `double` `N)` `{` ` ` `double` `val = N * N - ` `4.0` `* N;` ` ` `// Not possible` ` ` `if` `(val < ` `0` `) {` ` ` `System.out.println(` `"NO"` `);` ` ` `return` `;` ` ` `}` ` ` `// find a and b` ` ` `double` `a = (N + Math.sqrt(val)) / ` `2.0` `;` ` ` `double` `b = (N - Math.sqrt(val)) / ` `2.0` `;` ` ` `System.out.println(` `"a = "` `+a);` ` ` `System.out.println(` `"b = "` `+b);` `}` `// Driver Code` `public` `static` `void` `main(String[] args)` `{` ` ` `double` `N = ` `69.0` `;` ` ` `findAandB(N);` `}` `}` `// This Code is contributed by mits` |

## Python3

`# Python 3 program to find a and b` `# such that a*b=N and a+b=N` `from` `math ` `import` `sqrt` `# Function to return the` `# smallest string` `def` `findAandB(N):` ` ` `val ` `=` `N ` `*` `N ` `-` `4.0` `*` `N` ` ` `# Not possible` ` ` `if` `(val < ` `0` `):` ` ` `print` `(` `"NO"` `)` ` ` `return` ` ` ` ` `# find a and b` ` ` `a ` `=` `(N ` `+` `sqrt(val)) ` `/` `2.0` ` ` `b ` `=` `(N ` `-` `sqrt(val)) ` `/` `2.0` ` ` `print` `(` `"a ="` `, ` `'{0:.6}'` `. ` `format` `(a))` ` ` `print` `(` `"b ="` `, ` `'{0:.6}'` `. ` `format` `(b))` `# Driver Code` `if` `__name__ ` `=` `=` `'__main__'` `:` ` ` `N ` `=` `69.0` ` ` `findAandB(N)` ` ` `# This code is contributed` `# by SURENDRA_GANGWAR ` |

## C#

`// C# program to find a and b` `// such that a*b=N and a+b=N` `using` `System;` `class` `GFG` `{` `// Function to return the smallest string` `static` `void` `findAandB(` `double` `N)` `{` `double` `val = N * N - 4.0 * N;` `// Not possible` `if` `(val < 0) {` `Console.WriteLine(` `"NO"` `);` `return` `;` `}` `// find a and b` `double` `a = (N + Math.Sqrt(val)) / 2.0;` `double` `b = (N - Math.Sqrt(val)) / 2.0;` `Console.WriteLine(` `"a = "` `+a);` `Console.WriteLine(` `"b = "` `+b);` `}` `// Driver Code` `static` `void` `Main()` `{` `double` `N = 69.0;` `findAandB(N);` `}` `// This code is contributed by ANKITRAI1` `}` |

## PHP

`<?php` `// PHP program to find a and b` `// such that a*b=N and a+b=N` `// Function to return the` `// smallest string` `function` `findAandB(` `$N` `)` `{` ` ` `$val` `= ` `$N` `* ` `$N` `- 4.0 * ` `$N` `;` ` ` `// Not possible` ` ` `if` `(` `$val` `< 0)` ` ` `{` ` ` `echo` `"NO"` `;` ` ` `return` `;` ` ` `}` ` ` `// find a and b` ` ` `$a` `= (` `$N` `+ sqrt(` `$val` `)) / 2.0;` ` ` `$b` `= (` `$N` `- sqrt(` `$val` `)) / 2.0;` ` ` `echo` `"a = "` `, ` `$a` `, ` `"\n"` `;` ` ` `echo` `"b = "` `, ` `$b` `, ` `"\n"` `;` `}` `// Driver Code` `$N` `= 69.0;` `findAandB(` `$N` `);` `// This code is contributed by ajit` `?>` |

## Javascript

`<script>` ` ` `// Javascript program to find a and b` ` ` `// such that a*b=N and a+b=N` ` ` ` ` `// Function to return the smallest string` ` ` `function` `findAandB(N)` ` ` `{` ` ` `let val = N * N - 4.0 * N;` ` ` `// Not possible` ` ` `if` `(val < 0) {` ` ` `document.write(` `"NO"` `);` ` ` `return` `;` ` ` `}` ` ` `// find a and b` ` ` `let a = (N + Math.sqrt(val)) / 2.0;` ` ` `let b = (N - Math.sqrt(val)) / 2.0;` ` ` `document.write(` `"a = "` `+a.toFixed(4) + ` `"</br>"` `);` ` ` `document.write(` `"b = "` `+b.toFixed(5));` ` ` `}` ` ` ` ` `let N = 69.0;` ` ` `findAandB(N);` ` ` `</script>` |

**Output:**

a = 67.9851 b = 1.01493

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the **DSA Self Paced Course** at a student-friendly price and become industry ready. Get hold of all the important mathematical concepts for competitive programming with the **Essential Maths for CP Course** at a student-friendly price.

In case you wish to attend live classes with industry experts, please refer **Geeks Classes Live**