Find the sum of n terms of the series 1,8,27,64 ….

Given a series, the task is to find the sum of the below series up to n terms:

1, 8, 27, 64, …

Examples:

Input: N = 2
Output: 9
9 = (2*(2+1)/2)^2

Input: N = 4
Output: 100
100 = (4*(4+1)/2)^2

Approach: We can solve this problem using the following formula:

    Sn = 1 + 8 + 27 + 64 + .........up to n terms
    Sn = (n*(n+1)/2)^2

Below is the implementation opf above approach:

C++

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// C++ program to find the sum of n terms
#include <bits/stdc++.h>
using namespace std;
  
// Function to calculate the sum
int calculateSum(int n)
{
  
    // Return total sum
    return pow(n * (n + 1) / 2, 2);
}
  
// Driver code
int main()
{
  
    int n = 4;
    cout << calculateSum(n);
  
    return 0;
}

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Java














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// Java program to find the sum of n terms  


import java.io.*; 


  


class GFG { 


  


  


// Function to calculate the sum  


static int calculateSum(int n)  


{  


  


    // Return total sum  


    return (int)Math.pow(n * (n + 1) / 2, 2);  


}  


  


// Driver code  


  


  


    public static void main (String[] args) { 


        int n = 4;  


    System.out.println( calculateSum(n));  


  


    } 


} 


// This code is contributed by inder_verma.. 



















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Python3














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# Python3 program to find the  


# sum of n terms 


  


#Function to calculate the sum 


def calculateSum(n): 


      


    #return total sum 


    return (n * (n + 1) / 2)**2


      


#Driver code 


if __name__=='__main__': 


    n = 4


    print(calculateSum(n)) 


  


#this code is contributed by Shashank_Sharma 



















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C#














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// C# program to find the sum of n terms  


using System; 


  


class GFG  


{ 


  


// Function ot calculate the sum  


static int calculateSum(int n)  


{  


  


    // Return total sum  


    return (int)Math.Pow(n * (n + 1) / 2, 2);  


}  


  


// Driver code  


public static void Main () 


{ 


    int n = 4;  


    Console.WriteLine(calculateSum(n));  


} 


} 


  


// This code is contributed  


// by Akanksha Rai(Abby_akku) 



















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PHP














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<?php 


// PHP program to find  


// the sum of n terms  


      


// Function to calculate the sum  


function calculateSum($n) 


{ 


    // Return total sum  


    return pow($n * ($n + 1) / 2 , 2);  


} 


      


// Driver code 


$n = 4; 


echo calculateSum($n); 


      


// This code is contributed 


// by ANKITRAI1 


?> 



















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Output:


100







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