# Find the sum of n terms of the series 1,8,27,64 ….

Given a series, the task is to find the sum of the below series up to n terms:

1, 8, 27, 64, …

Examples:

```Input: N = 2
Output: 9
9 = (2*(2+1)/2)^2

Input: N = 4
Output: 100
100 = (4*(4+1)/2)^2
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: We can solve this problem using the following formula:

```    Sn = 1 + 8 + 27 + 64 + .........up to n terms
Sn = (n*(n+1)/2)^2
```

Below is the implementation opf above approach:

## C++

 `// C++ program to find the sum of n terms ` `#include ` `using` `namespace` `std; ` ` `  `// Function to calculate the sum ` `int` `calculateSum(``int` `n) ` `{ ` ` `  `    ``// Return total sum ` `    ``return` `pow``(n * (n + 1) / 2, 2); ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` ` `  `    ``int` `n = 4; ` `    ``cout << calculateSum(n); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find the sum of n terms  ` `import` `java.io.*; ` ` `  `class` `GFG { ` ` `  ` `  `// Function to calculate the sum  ` `static` `int` `calculateSum(``int` `n)  ` `{  ` ` `  `    ``// Return total sum  ` `    ``return` `(``int``)Math.pow(n * (n + ``1``) / ``2``, ``2``);  ` `}  ` ` `  `// Driver code  ` ` `  ` `  `    ``public` `static` `void` `main (String[] args) { ` `        ``int` `n = ``4``;  ` `    ``System.out.println( calculateSum(n));  ` ` `  `    ``} ` `} ` `// This code is contributed by inder_verma.. `

## Python3

 `# Python3 program to find the  ` `# sum of n terms ` ` `  `#Function to calculate the sum ` `def` `calculateSum(n): ` `     `  `    ``#return total sum ` `    ``return` `(n ``*` `(n ``+` `1``) ``/` `2``)``*``*``2` `     `  `#Driver code ` `if` `__name__``=``=``'__main__'``: ` `    ``n ``=` `4` `    ``print``(calculateSum(n)) ` ` `  `#this code is contributed by Shashank_Sharma `

## C#

 `// C# program to find the sum of n terms  ` `using` `System; ` ` `  `class` `GFG  ` `{ ` ` `  `// Function ot calculate the sum  ` `static` `int` `calculateSum(``int` `n)  ` `{  ` ` `  `    ``// Return total sum  ` `    ``return` `(``int``)Math.Pow(n * (n + 1) / 2, 2);  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `Main () ` `{ ` `    ``int` `n = 4;  ` `    ``Console.WriteLine(calculateSum(n));  ` `} ` `} ` ` `  `// This code is contributed  ` `// by Akanksha Rai(Abby_akku) `

## PHP

 ` `

Output:

```100
```

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