Find the sum of n terms of the series 1,8,27,64 ….

Given a series, the task is to find the sum of the below series up to n terms:

1, 8, 27, 64, …

Examples:

Input: N = 2
Output: 9
9 = (2*(2+1)/2)^2

Input: N = 4
Output: 100
100 = (4*(4+1)/2)^2

Approach: We can solve this problem using the following formula:

    Sn = 1 + 8 + 27 + 64 + .........up to n terms
    Sn = (n*(n+1)/2)^2

Below is the implementation opf above approach:

C++

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// C++ program to find the sum of n terms
#include <bits/stdc++.h>
using namespace std;
  
// Function to calculate the sum
int calculateSum(int n)
{
  
    // Return total sum
    return pow(n * (n + 1) / 2, 2);
}
  
// Driver code
int main()
{
  
    int n = 4;
    cout << calculateSum(n);
  
    return 0;
}

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Java

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// Java program to find the sum of n terms 
import java.io.*;
  
class GFG {
  
  
// Function to calculate the sum 
static int calculateSum(int n) 
  
    // Return total sum 
    return (int)Math.pow(n * (n + 1) / 2, 2); 
  
// Driver code 
  
  
    public static void main (String[] args) {
        int n = 4
    System.out.println( calculateSum(n)); 
  
    }
}
// This code is contributed by inder_verma..

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Python3

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# Python3 program to find the 
# sum of n terms
  
#Function to calculate the sum
def calculateSum(n):
      
    #return total sum
    return (n * (n + 1) / 2)**2
      
#Driver code
if __name__=='__main__':
    n = 4
    print(calculateSum(n))
  
#this code is contributed by Shashank_Sharma

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C#

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// C# program to find the sum of n terms 
using System;
  
class GFG 
{
  
// Function ot calculate the sum 
static int calculateSum(int n) 
  
    // Return total sum 
    return (int)Math.Pow(n * (n + 1) / 2, 2); 
  
// Driver code 
public static void Main ()
{
    int n = 4; 
    Console.WriteLine(calculateSum(n)); 
}
}
  
// This code is contributed 
// by Akanksha Rai(Abby_akku)

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PHP

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<?php
// PHP program to find 
// the sum of n terms 
      
// Function to calculate the sum 
function calculateSum($n)
{
    // Return total sum 
    return pow($n * ($n + 1) / 2 , 2); 
}
      
// Driver code
$n = 4;
echo calculateSum($n);
      
// This code is contributed
// by ANKITRAI1
?>

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Output:

100


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